Talk:Multishot (Mechanic)/@comment-6567499-20130421123301/@comment-122.151.143.187-20130806160900

Considering the fact you would need a WHOLE or EQUAL number (being our 100% multishot) in order to even fire the second bullet every single time. Which we don't have. How is that you think a third multiplier comes into play when firing a bullet that only has a 90% chance of making two bullets alone?