Talk:Status Effect/@comment-36.70.135.137-20150207085128/@comment-665695-20150223190656


 * Combined status chance for entire shot. You have to land all the pellets to get the most status chance out of the shot.

This statement is correct.


 * If your status chance is 30%, and you have 10 pellets but only hit with 1, it is only 3% status for that ONE pellet (cuz 30%/10 pellets is 3% per pellet)

This example is inaccurate. The actual mathematical calculation uses statistics, not merely arithmetic. If you wish to find the probability that at least one of the pellets procced, you should find the probability that none of them procced and then subtract that from 100%.

To work your "3% per pellet" example, that means that each pellet has a 97% chance of not proccing. Since the first pellet AND then second pellet AND the third pellet AND the fourth pellet AND... until the tenth pellet all need to not-proc, you have 97/100 * 97/100 * 97/100 * 97/100... until you have all ten pellets accounted for.

A percentage can also look like 0.97 to mean 97% (where 1.00 means 100%), and you can use exponentiation (^) to do a lot of multiplication of the same number quickly. So, a gun that shoots out 10 bullets with 3% chance of proccing per bullet would have a 1.00 - (0.97)^10 = 26.36% chance to proc at least once.

If your weapon's status chance is 30%, then we can rearrange the equation. We'd set up the equation like so: 0.30 = 1.00 - (?)^10 and then subtract from both sides. -0.70 = -(?)^10. Since the negative is on both sides, you can multiply both sides by -1 and get 0.70 = ?^10. Take the tenth root (use a calculator) of both sides to get 0.9650 as the chance that each single pellet doesn't proc. Subtracting that from 1.00 yields a 3.5% that each pellet has to proc.

One could argue that you were kinda close, but that's only happenstance. If your example weapon had a status chance much closer to 100%, and a pellet count that didn't divide nicely, you could have a wildly different answer than from the flawed math of the previous comment.