Talk:Tiberon/@comment-67.237.111.35-20141204192717/@comment-88.90.42.56-20141216094744

yeah, but you get three 5% chances, that increases the chance of at least one critical.

If you threw a dice three times would you expect the chances of rolling at least one 6 to be 1/6?

The general formula is: 1 - (A')^n      A' is the complement, or probability of event A not happening. n is the number of times event A can happen.

In this case we have 3 bullets with each pull of the trigger so n = 3

A is the chance for a bullet to be a critical hit = 0.05

A' = 1 - A = 1 - 0.05 = 0.95

The chance for at least one critical hit with a single trigger pull is then:

1 - (0.95)^3 = 1 - (0.95 * 0.95 * 0.95) = 1 - 0.857 = 0.143 = 14.3%